Mg + 2HCl MgCl₂ + H₂

Provide the mole ratio for each of the following mole conversions:

Mg to H₂: $LaTeX: (\frac{1molMg}{1molH_2})$ or $LaTeX: (\frac{1molH_2}{1molMg})$
HCl to H₂: $LaTeX: (\frac{2molHCl}{1molH_2})$ or $LaTeX: (\frac{1molH_2}{2molHCl})$
Mg to HCl: $LaTeX: (\frac{1molMg}{2molHCl})$ or $LaTeX: (\frac{2molHCl}{1molMg})$
MgCl₂ to HCl: $LaTeX: (\frac{1molMgCl_2}{2molHCl})$ or $LaTeX: (\frac{2molHCl}{1molMgCl_2})$

Ca₃P₂(s) + 6H₂O(l) 3Ca(OH)₂(s) + 2PH₃(g)

$LaTeX: 5.00molCa_3P_2\times(\frac{2molPH_3}{1molCa_3P_2})=$ 10.0 mol PH₃

$LaTeX: 5.00molH_2O\times(\frac{2molPH_3}{6molH_2O})=$ 1.67 mol PH₃

C₃H₈ + 5O₂ 3CO₂ + 4H₂O

$LaTeX: 45gC_3H_8\times(\frac{1molC_3H_8}{44.11gC_3H_8})\times(\frac{3molCO_2}{1molC_3H_8})=$ 3.06 mol CO₂

$LaTeX: 0.200molCO_2\times(\frac{4molH_2O}{3molCO_2})\times(\frac{18.02gH_2O}{1molH_2O})=$ 4.81g H₂O

$LaTeX: 1.80gH_2O\times(\frac{1molH_2O}{18.02gH_2O})\times(\frac{1molC_3H_8}{4molH_2O})\times(\frac{44.11gC_3H_8}{1molC_3H_8})=$ 1.10g C₃H₈

$LaTeX: 160gO_2\times(\frac{1molO_2}{32.00gO_2})\times(\frac{1molC_3H_8}{5molO_2})\times(\frac{44.11gC_3H_8}{1molC_3H_8})=$ 44g C₃H₈