Mixed Stoichiometry I Answer Key (CHEM 1405)
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Mg + 2HCl MgCl2 + H2
Provide the mole ratio for each of the following mole conversions:
- Mg to H2:
(1molMg1molH2) or
(1molH21molMg)
- HCl to H2:
(2molHCl1molH2) or
(1molH22molHCl)
- Mg to HCl:
(1molMg2molHCl) or
(2molHCl1molMg)
- MgCl2 to HCl:
(1molMgCl22molHCl) or
(2molHCl1molMgCl2)
Ca3P2(s) + 6H2O(l) 3Ca(OH)2(s) + 2PH3(g)
- How many moles of phosphine (PH3) are prepared from 5.00 moles of Ca3P2 ?
5.00molCa3P2×(2molPH31molCa3P2)= 10.0 mol PH3
- How many moles of phosphine (PH3) are prepared from 5.00 moles of H2O?
5.00molH2O×(2molPH36molH2O)= 1.67 mol PH3
C3H8 + 5O2 3CO2 + 4H2O
- How many moles of CO2 are produced from the combustion of 45 g of C3H8?
45gC3H8×(1molC3H844.11gC3H8)×(3molCO21molC3H8)= 3.06 mol CO2
- What mass of H2O is produced if 0.200 mole of CO2 is also produced?
0.200molCO2×(4molH2O3molCO2)×(18.02gH2O1molH2O)= 4.81g H2O
- What mass of C3H8 is required to produce 1.80 g of H2O?
1.80gH2O×(1molH2O18.02gH2O)×(1molC3H84molH2O)×(44.11gC3H81molC3H8)= 1.10g C3H8
- What mass of C3H8 is required to react with 160 g of O2?
160gO2×(1molO232.00gO2)×(1molC3H85molO2)×(44.11gC3H81molC3H8)= 44g C3H8