Mole Ratios and Mole Conversions Answer Key (CHEM 1405)
Back to Chemistry 1405 Practice Problems
Balance the following equations, and then write the mole ratios, using dimensional analysis.
1. N2 + 3H2 2NH3
a) write the ratio of nitrogen gas to hydrogen gas: 1molN23molH2 or
3molH21molN2
b) nitrogen gas to ammonia (NH3): 1molN22molNH3 or
2molNH31molN2
c) hydrogen gas to ammonia (NH3): 3molH22molNH3 or
2molNH33molH2
2. 8H2 + S8 8H2S
a) hydrogen gas to hydrogen sulfide: 8molH28molH2S or
8molH2S8molH2 (This ratio can be reduced to 1:1)
b) hydrogen gas to sulfur: 8molH21molS8 or
1molS88molH2
c) hydrogen sulfide to sulfur: 8molH2S1molS8 or
1molS88molH2S
3. CH4 + 2O2 CO2 + 2H2O
a) oxygen gas to carbon dioxide: 2molO21molCO2 or
1molCO22molO2
b) methane (CH4) to carbon dioxide: 1molCH41molCO2 or
1molCO21molCH4
c) methane (CH4) to water: 1molCH42molH2O or
2molH2O1molCH4
d) oxygen gas to water: 2molO22molH2O or
2molH2O2molO2
4. 2H2 + O2 2H2O
a) hydrogen gas to water: 2molH22molH2O or
2molH2O2molH2
b) If you had 20 moles of hydrogen gas, how many moles of water could you make?
20molH2×2molH2O2molH2= 20 mol H2O
c) oxygen gas to water: 1molO22molH2O or
2molH2O1molO2
d) If you had 20 moles of oxygen gas, how many moles of water could you make?
20molO2×2molH2O1molO2= 40 mol H2O
5. N2 + 3H2 2NH3
a) If 1 mole of nitrogen gas were used, how many moles of ammonia would be produced?
1molN2×2molNH31molN2= 2 mol NH3
b) If 10 moles of ammonia were produced, how many moles of nitrogen gas would be required?
10molNH3×1molN22molNH3= 5 mol N2
c) If 3.00 moles of hydrogen gas were used, how many moles of ammonia would be produced?
3.00molH2×2molNH33molH2= 2 mol NH3
d) If 0.600 moles of ammonia were produced, how many moles of hydrogen gas would be required?
0.600molNH3×3molH22molNH3= 0.900 mol H2
6. 2NaI + Cl2 2NaCl + I2
a) How many moles of sodium chloride would be produced when 5.00 moles of chlorine gas are used?
5.00molCl2×2molNaCl1molCl2= 10 mol NaCl
b) If 3.50 moles of sodium chloride are produced, how many moles of chlorine gas must be used?
3.50molNaCl×1molCl22molNaCl= 1.75 mol Cl2
c) Given the data in part b, how many moles of sodium iodide must be used?
3.50molNaCl×2molNaI2molNaCl= 3.50 mol NaI
d) If 4.75 moles of sodium iodide are used, how many moles of pure iodine are produced?
4.75molNaI×1molI22molNaI= 2.38 mol I2