Temperature Conversion Practice Answer Key (CHEM 1405)
Back to Chemistry 1405 Practice Problems
For problems 1-5, the following general equation is used: ∘C=59(∘F−32)
1) 75oF = ______________oC
∘C=59(75∘F−32)=24∘C
2) 0oF = ______________oC
∘C=59(0∘F−32)=−18∘C
3) 98.6oF = ____________oC
∘C=59(98.6∘F−32)=37.0∘C
4) 160oF = _____________oC
∘C=59(160∘F−32)=71∘C
5) -10oF = _____________oC
∘C=59(−10∘F−32)=−23∘C
For problems 6-10, the following general equation is used: ∘F=95∘C+32
6) 45oC = ______________oF
∘F=95(45∘C)+32=113∘F
7) 30oC = ______________oF
∘F=95(30∘C)+32=86∘F
8) -10oC = _____________oF
∘F=95(−10∘C)+32=14∘F
9) 200oC = _____________oF
∘F=95(200∘C)+32=392∘F
10) -40oC = ____________oF
∘F=95(−40∘C)+32=−40∘F